Optimal. Leaf size=251 \[ \frac {5 a^4 b x^2 \sqrt {a^2+2 a b x^2+b^2 x^4}}{2 \left (a+b x^2\right )}+\frac {5 a^3 b^2 x^4 \sqrt {a^2+2 a b x^2+b^2 x^4}}{2 \left (a+b x^2\right )}+\frac {5 a^2 b^3 x^6 \sqrt {a^2+2 a b x^2+b^2 x^4}}{3 \left (a+b x^2\right )}+\frac {5 a b^4 x^8 \sqrt {a^2+2 a b x^2+b^2 x^4}}{8 \left (a+b x^2\right )}+\frac {b^5 x^{10} \sqrt {a^2+2 a b x^2+b^2 x^4}}{10 \left (a+b x^2\right )}+\frac {a^5 \sqrt {a^2+2 a b x^2+b^2 x^4} \log (x)}{a+b x^2} \]
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Rubi [A]
time = 0.04, antiderivative size = 251, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 3, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.115, Rules used = {1126, 272, 45}
\begin {gather*} \frac {b^5 x^{10} \sqrt {a^2+2 a b x^2+b^2 x^4}}{10 \left (a+b x^2\right )}+\frac {5 a b^4 x^8 \sqrt {a^2+2 a b x^2+b^2 x^4}}{8 \left (a+b x^2\right )}+\frac {5 a^2 b^3 x^6 \sqrt {a^2+2 a b x^2+b^2 x^4}}{3 \left (a+b x^2\right )}+\frac {a^5 \log (x) \sqrt {a^2+2 a b x^2+b^2 x^4}}{a+b x^2}+\frac {5 a^4 b x^2 \sqrt {a^2+2 a b x^2+b^2 x^4}}{2 \left (a+b x^2\right )}+\frac {5 a^3 b^2 x^4 \sqrt {a^2+2 a b x^2+b^2 x^4}}{2 \left (a+b x^2\right )} \end {gather*}
Antiderivative was successfully verified.
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Rule 45
Rule 272
Rule 1126
Rubi steps
\begin {align*} \int \frac {\left (a^2+2 a b x^2+b^2 x^4\right )^{5/2}}{x} \, dx &=\frac {\sqrt {a^2+2 a b x^2+b^2 x^4} \int \frac {\left (a b+b^2 x^2\right )^5}{x} \, dx}{b^4 \left (a b+b^2 x^2\right )}\\ &=\frac {\sqrt {a^2+2 a b x^2+b^2 x^4} \text {Subst}\left (\int \frac {\left (a b+b^2 x\right )^5}{x} \, dx,x,x^2\right )}{2 b^4 \left (a b+b^2 x^2\right )}\\ &=\frac {\sqrt {a^2+2 a b x^2+b^2 x^4} \text {Subst}\left (\int \left (5 a^4 b^6+\frac {a^5 b^5}{x}+10 a^3 b^7 x+10 a^2 b^8 x^2+5 a b^9 x^3+b^{10} x^4\right ) \, dx,x,x^2\right )}{2 b^4 \left (a b+b^2 x^2\right )}\\ &=\frac {5 a^4 b x^2 \sqrt {a^2+2 a b x^2+b^2 x^4}}{2 \left (a+b x^2\right )}+\frac {5 a^3 b^2 x^4 \sqrt {a^2+2 a b x^2+b^2 x^4}}{2 \left (a+b x^2\right )}+\frac {5 a^2 b^3 x^6 \sqrt {a^2+2 a b x^2+b^2 x^4}}{3 \left (a+b x^2\right )}+\frac {5 a b^4 x^8 \sqrt {a^2+2 a b x^2+b^2 x^4}}{8 \left (a+b x^2\right )}+\frac {b^5 x^{10} \sqrt {a^2+2 a b x^2+b^2 x^4}}{10 \left (a+b x^2\right )}+\frac {a^5 \sqrt {a^2+2 a b x^2+b^2 x^4} \log (x)}{a+b x^2}\\ \end {align*}
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Mathematica [A]
time = 0.02, size = 82, normalized size = 0.33 \begin {gather*} \frac {\sqrt {\left (a+b x^2\right )^2} \left (b x^2 \left (300 a^4+300 a^3 b x^2+200 a^2 b^2 x^4+75 a b^3 x^6+12 b^4 x^8\right )+120 a^5 \log (x)\right )}{120 \left (a+b x^2\right )} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.02, size = 79, normalized size = 0.31
method | result | size |
default | \(\frac {\left (\left (b \,x^{2}+a \right )^{2}\right )^{\frac {5}{2}} \left (12 b^{5} x^{10}+75 b^{4} a \,x^{8}+200 a^{2} b^{3} x^{6}+300 b^{2} a^{3} x^{4}+300 b \,a^{4} x^{2}+120 a^{5} \ln \left (x \right )\right )}{120 \left (b \,x^{2}+a \right )^{5}}\) | \(79\) |
risch | \(\frac {\sqrt {\left (b \,x^{2}+a \right )^{2}}\, b \left (\frac {1}{10} b^{4} x^{10}+\frac {5}{8} a \,b^{3} x^{8}+\frac {5}{3} a^{2} b^{2} x^{6}+\frac {5}{2} a^{3} b \,x^{4}+\frac {5}{2} a^{4} x^{2}\right )}{b \,x^{2}+a}+\frac {a^{5} \ln \left (x \right ) \sqrt {\left (b \,x^{2}+a \right )^{2}}}{b \,x^{2}+a}\) | \(96\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.29, size = 55, normalized size = 0.22 \begin {gather*} \frac {1}{10} \, b^{5} x^{10} + \frac {5}{8} \, a b^{4} x^{8} + \frac {5}{3} \, a^{2} b^{3} x^{6} + \frac {5}{2} \, a^{3} b^{2} x^{4} + \frac {5}{2} \, a^{4} b x^{2} + a^{5} \log \left (x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.34, size = 55, normalized size = 0.22 \begin {gather*} \frac {1}{10} \, b^{5} x^{10} + \frac {5}{8} \, a b^{4} x^{8} + \frac {5}{3} \, a^{2} b^{3} x^{6} + \frac {5}{2} \, a^{3} b^{2} x^{4} + \frac {5}{2} \, a^{4} b x^{2} + a^{5} \log \left (x\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {\left (\left (a + b x^{2}\right )^{2}\right )^{\frac {5}{2}}}{x}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 3.71, size = 106, normalized size = 0.42 \begin {gather*} \frac {1}{10} \, b^{5} x^{10} \mathrm {sgn}\left (b x^{2} + a\right ) + \frac {5}{8} \, a b^{4} x^{8} \mathrm {sgn}\left (b x^{2} + a\right ) + \frac {5}{3} \, a^{2} b^{3} x^{6} \mathrm {sgn}\left (b x^{2} + a\right ) + \frac {5}{2} \, a^{3} b^{2} x^{4} \mathrm {sgn}\left (b x^{2} + a\right ) + \frac {5}{2} \, a^{4} b x^{2} \mathrm {sgn}\left (b x^{2} + a\right ) + \frac {1}{2} \, a^{5} \log \left (x^{2}\right ) \mathrm {sgn}\left (b x^{2} + a\right ) \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (a^2+2\,a\,b\,x^2+b^2\,x^4\right )}^{5/2}}{x} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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